Question on elevation change

[Michael54]

My longest flat shot on my farm is 350 yards we have a target set up for that shot. However there is a section i could stretch to 675ish but there is probably a 20' drop from where im shooting to where the target would be? How much would that affect my trajectory if at all? Im not a long range guy by nature but do believe the further you practice the easier it is in close. I just have a bdc reticle with hold points and can never really see myself dialing in a scope before shots.

 

[Cahunter805]

Does your rangefinder have angle compensation? It will give your the corrected yardage to your target. It shouldn’t be much of a change though.

 

[Michael54]

Does your rangefinder have angle compensation? It will give your the corrected yardage to your target. It shouldn’t be much of a change though.

I have a scout arc 1000. It just has modes i do believe? I know there's an archery mode and brush mode so im assuming the angle compensator is automatic in it?

 

[jritterbeck]

 

[Broz]

20' of shot angle over 675 yards is not going to change corrections very much.

Jeff

 

[Michael54]

20' of shot angle over 675 yards is not going to change corrections very much.

Jeff

Im just figuring on hanging a 12" steel plate out there. I have them in 100 yard increments right now. Its definitely helped me with knowing my hold points on my bdc scope. My thoughts are if i can practice at 675 ish a 300 yard shot will become easier.

 

[Mike Islander]

Pathagorean Theorem
A^2+B^2=C^2
A=674. 96
B=7
C=675 YARDS

So no meaningful difference.

 

[Low_Sky]

You don’t have fine enough adjustment in your scope turrets to even make the (extremely small) correction. 20’ over 675 yards is effectively nothing.


Sent from my iPhone using Tapatalk

 

[LaHunter]

Pathagorean Theorem
A^2+B^2=C^2
A=675
B=20
C=675.3 YARDS

So no meaningful difference.

You have the correct formula, but 'C' would be the 675 yards line of sight distance. 'A' would be the 'shoot to' distance, which would be less than 'C'. And 'B' is the 20' elevation difference, so about 7 yards (need to keep the units the same). You would have to solve for 'A'. Bottom line is the 'shoot to' distance is essentially still 675

 

[Mike Islander]

You have the correct formula, but 'C' would be the 675 yards line of sight distance. 'A' would be the 'shoot to' distance, which would be less than 'C'. And 'B' is the 20' elevation difference, so about 7 yards (need to keep the units the same). You would have to solve for 'A'. Bottom line is the 'shoot to' distance is essentially still 675

Appreciate the correction. 20' = 7 yards for short side and 675 yards hypotenuse (c). Less than 1.5" total difference.

 

[gfreidy]

Love the math! Great to use it for something so love to do

 

[Michael54]

Pathagorean Theorem
A^2+B^2=C^2
A=675
B=20
C=675.3 YARDS

So no meaningful difference.

If my geometry teacher answered with this when i asked him how id use it in real life id have paid attention more lol.

 

[Jimss]

I just bought a pair of Leica binos with rangefinder. It has a chip in it that you can input your caliber, load, etc. before heading out shooting. All you need to do is press a button and it compensates everything.....pretty nice!