Jaden Bales
WKR
How would one calculate the odds of drawing 1 of your 5 choices in Nevada?
Better question, what are the odds anyone wants to try and tackle this math?
Here's the situation.
I got all trigger happy and applied for Nevada before mapping out my hunting budget for the year. Went to get a refund (since app date is April 29) and that is not possible. Totally get it. No problems there. So, I'll stick with my plan to try and pull a tag and if I do, I'll just sell my body or something to make sure I can go. No problems there either.
Now, I am trying to figure out what the chances of drawing just ANY of my units using GoHunt's per unit draw odds and costing me another...costing me a good chunk of change to do the hunt.
I come up with the following formula using this article: https://math.stackexchange.com/questions/91998/probability-of-winning-a-prize-in-a-raffle
C = Individual Unit Draw Odds
5 = Total Draw Choices
(C1 + C2 + C3 + C4 + C5)/5 = Average Draw Odds (ADO)
1 - ADO = Average Fail Odds (AFO)
(AFO)^5 = Odds of Failing to Draw (OFD)
1 - OFD = Odds of Drawing Tag
Bottom Line: If your 5 choices average out to 10% draw odds, you actually have 40% draw odds of pulling ONE tag of the 5 that year.
Does that make sense to anybody?
Better question, what are the odds anyone wants to try and tackle this math?
Here's the situation.
I got all trigger happy and applied for Nevada before mapping out my hunting budget for the year. Went to get a refund (since app date is April 29) and that is not possible. Totally get it. No problems there. So, I'll stick with my plan to try and pull a tag and if I do, I'll just sell my body or something to make sure I can go. No problems there either.
Now, I am trying to figure out what the chances of drawing just ANY of my units using GoHunt's per unit draw odds and costing me another...costing me a good chunk of change to do the hunt.
I come up with the following formula using this article: https://math.stackexchange.com/questions/91998/probability-of-winning-a-prize-in-a-raffle
C = Individual Unit Draw Odds
5 = Total Draw Choices
(C1 + C2 + C3 + C4 + C5)/5 = Average Draw Odds (ADO)
1 - ADO = Average Fail Odds (AFO)
(AFO)^5 = Odds of Failing to Draw (OFD)
1 - OFD = Odds of Drawing Tag
Bottom Line: If your 5 choices average out to 10% draw odds, you actually have 40% draw odds of pulling ONE tag of the 5 that year.
Does that make sense to anybody?